Continuing our tradition, we gave you yet another delicious brainteaser, to make your Monday a little more exciting.

Now it’s time to present your its savoury solution.

## The Fruit Basket Brain Teaser

Well, that is a healthy choice of living right there! Now let’s look at the solution.

## The Solution for the Brainteaser

So in this puzzle we get 40 cherries for $1, we get 1 orange for $3 and a watermelon for $5. Now we have $100 and we are to purchase 100 fruits for exactly that amount.

**We need to buy 100 fruits for $100.**

*Let’s take cherries to begin with, since you can buy them in large quantities at a minimal price*

$1 = 40 Cherries

$2 = 80 Cherries

$3 = 120 Cherries

Since, 120 is greater than 100

*Purchasing 100 cherries for $100 is out of the question.*

*Now let’s move on to buying just Oranges*

$3 = 1 Orange

Then for $100 you will get 33 Oranges.

*This also does not fulfill our 100 fruits for $100 criteria.*

*Let’s move onto Watermelon*

$5 = 1 Watermelon

Then for $100 you will get 20 Oranges

*This does not fulfill our criteria either*

With this trial and error, one point is clear, you cannot buy just one type of fruit here, you will have to buy a combination of them to full the condition of 100 fruits for $100.

Now, which is the fruit that we can buy the maximum number of in the minimum amount?

Yes, you are correct, it’s cherries.

**And the maximum number of cherries we can buy is 40 in $2.**

Now the money remaining with us is $98 and the number of fruits, 20, which should include oranges and watermelons.

To figure out how many fruits and watermelons we are suppose to buy for $98, let’s form two equations.

#### Equations

eq1 -The number of Oranges and Watermelons should be 20

i.e.

** O + W = 20**

eq2 – $3Oranges with $5Watermelons should amount to $98

i.e.

**3.O + 5.W = 98**

So the two equation we have are,

**O + W = 20**

**3.O + 5.W = 98**

Solve the two equations,

W can be written as

**W = 20 – O** (From eq 1)

Solving equation 2 by replacing W with 20 – O

**3.O + 5.(20 – O) = 98
3.O + 100 – 5.O = 98
100 – 2.O = 98
100 – 98 = 2.O
2 = 2.O**

Hence,

**O = 1**

Going back to equation 1 and putting the value of O in it

1 + W = 20

W = 2o -1

**W = 19**

So now we know that the number of Oranges we are to buy is 1 and the number of watermelons we should buy is 19.

**So we spend $3 to buy 1 Orange**

The amount left with us is **$95 with which we will buy 19 Watermelons (95/5 = 19 for verification)**

And this is your mouth watering solution to this delicious puzzle. Stay tuned for more brainteasers and there solutions.

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